give geometry ,shape,no.of lone pairs and bond pair on central atom N in NO₃^-

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Solution

$H y b r i d i s a t i o n = \frac{1}{2} [v a l e n c e n o o f e l e c t r o n o n t h e c e n t r a l m e t a l a t o m + n u m b e r o f s u r r o u n d i n g m o n o v a l e n t a t o m - c a t i o n + a n i o n] F o r N {O_{3}}^{-} H = \frac{1}{2} [5 + 0 - 0 + 1] = \frac{6}{2} = 3 = s p^{2} N u m b e r o f l o n e p a i r = H y b r i d i s a t i o n n u m b e r - n u m b e r o f s u r r o u n d i n g a t o m = 3 - 3 = 0 S o t h e h y b r i d i s a t i o n i s s p^{2} S h a p e i s T r i a n g u l a r s h a p e N o o f l o n e p a i r = 0 N o o f b o n d p a i r = 3$

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