give hybridisation state of each carbon in following compound:
(i) CH_3CH_2-
(ii) CH_3CH_2+

Open in App

Solution

1. $C H_{3} - C {H_{2}}^{-}$

Hybridisation of both the carbon atom is sp³. Second carbon is a carbanion,so negative charge occupies a sp³ orbital.

2. $C H_{3} - C {H_{2}}^{+}$

Hybridisation of CH₃- carbon is sp³ and of CH₂⁺ carbon is sp².

Suggest Corrections

Similar questions

C H_{3} C H_{2} - I I

C H_{3} C H_{2} - B r I i

C H_{3} C H_{2} - C l I i i

C H_{3} C H_{2} - F I V

C H_{3} C H_{2} - C H_{2} - O H

C H_{3} C H_{2} - (C H_{3}) C H - O H

C H_{3} C H_{2} - C H_{3} | C | C H_{3} - O H

C H_{3} i - O | | C i i - C H_{2} i i i - C N i v

C l - C H_{2} C O O H

C H_{3} C O O H

C H_{3} C H_{2} - C O - C H_{3}

C H_{3} C H_{2} - C H_{2} - C O - C H_{3}

C - C u

C H_{3} C H_{2} C u

Join BYJU'S Learning Program