Question

The hybridisation of each carbon in the following compound is:
$\underset{i}{C{H}_3}-\underset{ii}{\stackrel{\stackrel{O}{||}}{C}}-\underset{iii}{C{H}_2}-\underset{iv}{CN}$

• A. $s{p}^{3}s{p}^{2}s{p}^{3}sp$
• B. $s{p}^{3}s{p}^{3}s{p}^{2}sp$
• C. $s{p}^{3}sps{p}^{3}s{p}^2$
• D. $s{p}^{3}s{p}^{2}sps{p}^3$

Answer 1

The correct option is A $s{p}^{3}s{p}^{2}s{p}^{3}sp$

$\underset{i}{C{H}_3}-\underset{ii}{\stackrel{\stackrel{O}{||}}{C}}-\underset{iii}{C{H}_2}-\underset{iv}{CN}$

In (i), all single bonds occur therefore $s{p}^3$ hybridization.

In (ii), one double bond occurs therefore $s{p}^2$ hybridization.

In (iiI), all single bond occurs therefore $s{p}^3$ hybridization.

In (iv), one triple bond occurs, therefore $sp$ hybridization.