Question

Give reason for the following :
$PbC{l}_4$ is more covalent than $PbC{l}_2$.

Answer 1

Because $Pb$ is in $+4$ oxidation state in $PbC{l}_4$ and has high charge/ size ratio than $P{b}^{2+}$, thus polarising power of $P{b}^{4+}$ is greater than $P{b}^{2+}$, and hence it is more covalent.