Question

Give reason :
$\left[Ti\right(H_{2}O{)}_6{]}^{3+}$ is coloured while $\left[Sc\right(H_{2}O{)}_6{]}^{3+}$ is colourless

Answer 1

$\left[Ti\right(H_{2}O{)}_6{]}^{3+}$ is coloured while $\left[Sc\right(H_{2}O{)}_6{]}^{3+}$ is colourless This is because, in $Ti(H2O{)}_6$ has unpaired electron for d-d transition( responsible for colorness of a complex compound) so it is coloured .while $Sc(H2O{)}_6$ can not undergo d-d Transition as do not have unpaired electrons so it is colorless.