wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Give reasons for the following:

(i) o-nitrophenol is more acidic than o-methoxyphenol.

(ii) Butan-1-ol has a higher boiling point than diethyl ether.

(iii) (CH3)3COCH3 on reaction with HI gives (CH3)3CI and CH3OH as the main products and not (CH3)3C–OH and CH3I.

Open in App
Solution

(i) The nitro group (NO2) is an electron-withdrawing group. It decreases the density in the O–H bond. Thus, the proton can be easily lost. With the presence of an electron-withdrawing group, the phenoxide ion is more stabilised. Due to the high stability of the phenoxide ion, the acidic nature increases. On the other hand, the methoxy group is an electron-releasing group. It increases the density in the O–H bond. Thus, the proton cannot be given out easily. Thus, the phenoxide ion is less stabilised. Due to this, o-nitrophenol is more acidic than omethoxyphenol.

(ii) Butan-1-ol has a higher boiling point because it contains a hydroxyl group which is capable of hydrogen bonding. Molecules of diethyl ether are incapable of forming hydrogen bonds with each other.

(iii) (CH3)3COCH3 is an ether with two different alkyl groups, of which (CH3)3C , tertiary alkyl group, on reaction with hydrogen halide (HI) forms a tertiary halide. This occurs as the reaction is an SN1 reaction. The reaction involves the formation of a stable carbocation. If the ether has a primary alkyl group, then the reaction follows the SN2 mechanism.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Inductive Effect
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon