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Halogen Exchange Reactions

Give the bala...

Question

Give the balance equation for the following laboratory preparation :
Ethane from sodium propionate

C H_{3} C H_{2} C O O N a + N a O H \to C_{2} H_{6} + N a_{2} C O_{3}

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C H_{3} C H_{2} C O O N a + 2 N a O H \to C_{2} H_{4} + N a_{2} C O_{3}

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C H_{3} C H_{2} C O O N a + N a O H \to C_{2} H_{4} + N a_{2} C O_{3}

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C H_{3} C H_{2} C O O N a + 2 N a O H \to 2 C H_{4} + N a_{2} C O_{3}

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Solution

The correct option is A $C H_{3} C H_{2} C O O N a + N a O H \to C_{2} H_{6} + N a_{2} C O_{3}$
Reaction:
$C H_{3} C H_{2} C O O N a + N a O H \to C_{2} H_{6} + N a_{2} C O_{3}$

Suggest Corrections

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N a O H

C a (O H)_{2}

N a_{2} C O_{3} + C a (O H)_{2} \to 2 N a O H + C a C O_{3} ↓

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N a O H

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N H_{2} C O N H_{2} + 2 N a O H ⟶ 2 N H_{3} + N a_{2} C O_{3}

N H_{3}

${C O}_{2} + 2 N a O H \to H_{2} O + X :$

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N a H C O_{3}

N a_{2} C O_{3}

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N a_{2} C O_{3} + B a (O H)_{2} \to B a C O_{3} + 2 N a O H

N a H C O_{3} + B a (O H)_{2} \to B a C O_{3} + N a O H + H_{2} O

N a H C O_{3}

C H_{4}

C H_{3} C O O N a + N a O H C a O / Δ - --- \to C H_{4} + N a_{2} C O_{3}

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