Question

Give the balanced equation for the following reaction:

Lead sulphate from Lead nitrate solution and dilute sulphuric acid.

Answer 1

When 1mol of lead nitrate ($Pb{\left(N{O}_3\right)}_2$) reacts with 1mol of dilute sulphuric acid ($H_{2}S{O}_4$), 1 mol of Lead sulphate ($PbS{O}_4$) and $2$ moles of nitric acid ($HN{O}_3$) are produced.

Balanced chemical reaction:

${\text{Pb(NO}}_3{\text{)}}_2\left(\mathrm{aq}\right){\text{+ dil. H}}_2{\text{SO}}_4\left(\mathrm{aq}\right)\stackrel{}{\to }{\text{PbSO}}_4\left(\mathrm{s}\right){\text{+ 2HNO}}_3\left(\mathrm{aq}\right)$