Question

Give the empirical formula of:

Benzene $\left(C_6{H}_6\right)$

Glucose $\left(C_6{H}_{12}{O}_6\right)$

Acetylene $\left(C_2{H}_2\right)$

Hydrogen per oxide $\left(H_2{O}_2\right)$

Answer 1

Empirical formula $\to$ A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

In other words, empirical formula can be defined as the simplest form of molecular formula.

(A) Benzene $\left(C_6{H}_6\right)$-

Ratio of atoms-

$C:H=6:6=1:1$

$\therefore$ Empirical formula will be $\to CH$

(B) Glucose $\left(C_6{H}_{12}{O}_6\right)$-

Ratio of atoms-

$C:H:O=6:12:6=1:2:1$

$\therefore$ Empirical formula will be $\to C{H}_{2}O$

(C) Acetylene $\left(C_2{H}_2\right)$-

Ratio of atoms-

$C:H=2:2=1:1$

$\therefore$ Empirical formula will be $\to CH$

(A) Hydrogen per oxide $\left(H_2{O}_2\right)$-

Ratio of atoms-

$H:O=2:2=1:1$

$\therefore$ Empirical formula will be $\to HO$