Question

Give the factorization of 64a³-343b³ ?

Answer 1

64a3–343b3=(4a)3–(7b)3

We know that x3–y3 =(x–y)(x2+xy+y2)

∴(4a)3–(7b)3=(4a–7b)[(4a)2+(7b)(4a)+(7b)2]

=(4a–7b)(16a2+49b2+28ab)

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