Give the formula of each of the following coordination entities:
(i) $C o^{3 +}$ ion is bound to one $C l^{-}$ , one $N H_{3}$ molecule and two bidentate ethylene diamine (en) molecule.
(ii) $N i^{2 +}$ ion is bound to two water molecules and two oxalate ions.
Write the name and magnetic behavior of each of the above coordination entities. (At. no.: Co = 27, Ni = 28)

Open in App

Solution

I) $[C o (N H_{3}) (e n)_{2} C l]^{+ 2}$
Name of the compound is amminebis-(ethylenediamine)chlorido cobalt (III) ion. Number of unpaired electron are 4. So, the compound is paramagnetic.
II) [ $N i (H_{2} O)_{2} (C_{2} O_{4})_{2}]^{- 2}$
Name of the compound is diquadoxalato nickelate(II) ion. Number of unpaired electrons are 2. So, the compound is paramagnetic.

Suggest Corrections

Similar questions

N i^{2 +}

[P t (N H_{3}) C l (N O_{2})]

[C o (N H_{3})_{4} C l_{2}] C l

N i (C O)_{4}

C o = 27, N i = 28, P t = 78

[C o (e n)_{2} C l_{2}]^{+} (e n = e t h a n e - 1, 2 - d i a m i n e)

[C r (C_{2} O_{4})_{3}]^{3 -}

[C o (N H_{3})_{3} C l_{3}]

C r = 24, C o = 27

[C r (N H_{3})_{4} C l_{2}] C l

[C o (e n)_{3}]^{3 +}

[N i C l_{4}]^{2 -}

[N i (C O)_{4}]

Join BYJU'S Learning Program