Question

Given , 13 sin A = 5 . Evaluate $\frac{4sinA-3cosA}{tanA}.$

Answer 1

$sinA=5/13$

$cosA=\frac{12}{13}$

$tanA=5/12$

So, $\frac{4sinA-3cosA}{tanA}=\frac{4\left(5/13\right)-3\left(12/13\right)}{5/12}=\frac{-192}{65}$