Question

Given $(2a-3,3b+1)=(7,7)$; find $a$ and $b$.

• A. $a=5$ and $b=2$
• B. $a=-5$ and $b=2$
• C. $a=5$ and $b=-2$
• D. $a=-5$ and $b=-2$

Answer 1

The correct option is A $a=5$ and $b=2$

Given that $(2a-3,3b+1)=(7,7)$

Since, the ordered pairs are equal, then

$2a-3=7$

$\Rightarrow 2a=7+3$

$\Rightarrow 2a=10$

$\Rightarrow a=5$

and $3b+1=7$

$\Rightarrow 3b=7-1=6$

$\Rightarrow b=2$

Therefore, the values of $a=5$ and $b=2$.