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Fluorides of Xenon

Given: 2NOg...

Question

Given: $2 N O (g) + O_{2} (g) ⇋ N O_{2} (g); K_{1}$
$2 {N O}_{2} (g) ⇋ N_{2} O_{4} (g); K_{2}$
$2 N O (g) + O_{2} (g) ⇋ N_{2} O_{4} (g); K_{3}$
Which of the following relations is correct?

A

K_{3} = K_{1} / K_{2}

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B

K_{3} = K_{1} \times K_{2}

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C

K_{3} = K_{1} + K_{2}

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D

K_{3} = K_{1} / \sqrt{K_{2}}

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Solution

The correct option is B $K_{3} = K_{1} \times K_{2}$
Given: $2 N O (g) + O_{2} (g) ⇋ N O_{2} (g); K_{1}$ ....(1)
$2 {N O}_{2} (g) ⇋ N_{2} O_{4} (g); K_{2}$ ....(2)
$2 N O (g) + O_{2} (g) ⇋ N_{2} O_{4} (g); K_{3}$ ....(3)
The following relations is correct.
$K_{3} = K_{1} \times K_{2}$
When balanced equations (1) and (2) are added together, equation (3) is obtained.
When balanced equations are added together, the equilibrium constant for the combined process is equal to the product of the equilibrium constants for each step.

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Similar questions

N_{2} + O_{2} ⇌ 2 N O, K_{1}

;

(\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2} ⇌ N O, K_{2}

;

2 N O ⇌ N_{2} + O_{2}; K_{3}

;

N O ⇌ (\frac{1}{2}) N_{2} + (\frac{1}{2}) O_{2}; K_{4}

Correct relation(s) between

K_{1}, K_{2}, K_{3}

K_{4}

Q. For the reaction,

2 N H_{3} \to N_{2} + 3 H_{2}

- \frac{Δ [N H_{3}]}{Δ t} = K_{1} [N H_{3}]; \frac{Δ [N_{2}]}{Δ t} = K_{2} [N H_{3}]; \frac{Δ [H_{2}]}{Δ t} = K_{3} [N H_{3}]

Then relation between

k_{1}, k_{2}

k_{3}

For $C u^{2 +}$ ion in $[C u (H_{2} O)_{4} (e n)]^{2 +}, [C u (H_{2} O)_{2} (e n)_{2}]^{2 +}$ and $[C u (e n)_{3}]^{2 +}$ with the stability constant $k_{1}, k_{2}$ and $k_{3}$ respectively, which of the following holds true?

For these chemical equilibriums:

N_{2} + O_{2} ⇋ 2 N O, K_{1}

\frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇋ N O, K_{2}

2 N O ⇌ N_{2} + O_{2}; K_{3}

N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}, K_{4}

K_{1} \times K_{3} = x; \sqrt{(K_{1})} \times K_{4} = y; \sqrt{(K_{3})} \times K_{2} = z

What will be the value of

x y z

Q. For the reaction;

N_{2} O_{5} ⟶ 2 {N O}_{2} + \frac{1}{2} O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}]

- \frac{d [{N O}_{2}]}{d t} = K_{2} [{N O}_{2}]

- \frac{d [O_{2}]}{d t} = K_{3} [O_{2}]

The relation between

K_{1}, K_{2}, K_{3}

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