We are given a $4$ digit number using digits $1$ to $9$ .What is the maximum $3$ digit number that we can make by removing one digit from the given integer ?

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Solution

Compute the maximum $3$ digit number.
To get the greatest $3$ digit number, we need to simplify the given number i.e $5964$ by removing the smallest digit from it.
Hence, the number that is formed is $569$ or $965$ .

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Q. How many

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What is the total number of even non-negative integers that can be formed by using the digits 0, 1, 3, 5, 7 and 9, where repetition of digits isnotallowed?

Ans :

Number of 1-digit even numbers = 0

Number of 2-digit even numbers = 5×1 = 5

Number of 3-digit even numbers = 5×4×1 = 20

Number of 4-digit even numbers = 5×4×3×1 = 60

Number of 5-digit even numbers = 5×4×3×2×1 = 120

Number of 6-digit even numbers = 5×4×3×2×1×1 = 120

Note:Here, the units place digit is always occupied by 0.

Total number of even non-negative integers that can be formed by using digits 0, 1, 3, 5, 7 and 9, where repetition of digits is not allowed = 0 + 5 + 20 + 60 + 120 + 120 = 325

The correct answer is given by option A.

AS UNDERLINED ABOVE,0 IS AN EVEN NON NEGATIVE INTEGER.WHY AREN'T WE CONSIDERING IT

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We are given a 4 digit number using digits 1 to 9.What is the maximum 3 digit number that we can make by removing one digit from the given integer ?

Compute the maximum 3 digit number.To get the greatest 3 digit number, we need to simplify the given number i.e 5964 by removing the smallest digit from it.Hence, the number that is formed is 569 or 965.

We are given a $4$ digit number using digits $1$ to $9$ .What is the maximum $3$ digit number that we can make by removing one digit from the given integer ?

Compute the maximum $3$ digit number.
To get the greatest $3$ digit number, we need to simplify the given number i.e $5964$ by removing the smallest digit from it.
Hence, the number that is formed is $569$ or $965$ .