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Question

Given a rectangle of length a and breadth b:


In another rectangle, the length is 2 units more than the length and breadth is 3 units less than the breadth of the given rectangle.
Represent the area of another rectangle as an algebraic expression.

A
ab3a2b+6
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B
ab3a+2b6
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C
ab
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D
ab+2b6
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Solution

The correct option is B ab3a+2b6
We are given with a recatngle as shown:


Length of another rectangle is 2 units more than the length of the given rectangle.
Length of another rectangle =a+2

Breadth of another rectangle is 3 units less than the breadth of the given rectangle.
Breadth of another rectangle =b3

Another rectangle can be shown as:



Area of another rectangle
= Length × Breadth
=(a+2)×(b3)

This area can be evaluated using distributive property as:
(a+2)×(b3)
=a(b3)+2(b3)
=(a×b)(a×3)
+(2×b)(2×3)
=ab3a+2b6

The algebraic expresion of area of other rectangle is ab3a+2b6. Therefore, option (b.) is the correct answer.

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