Given A - x-x - N and 3 - x - 6 and B - x-x - W and x - 4- Find the sets A and B in roster form also find A- B and A- B-

Given A = { x:x ∈ N and 3 lt; x ≤ 6} and B = { x:x ∈ W and x lt; 4} .Then, A={4,5,6} and B={0,1,2,3} .Then A∪ B={0,1 ...

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Byju's Answer

Standard VIII

Mathematics

Roster Form

Given A = x...

Question

Given $A = {x : x \in N$ and $3 < x \leq 6}$ and $B = {x : x \in W$ and $x < 4}$ . Find the sets $A$ and $B$ in roster form also find $A \cup B$ and $A \cap B$ .

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Solution

Given $A = {x : x \in N$ and $3 < x \leq 6}$ and $B = {x : x \in W$ and $x < 4}$ .

Then,

$A = {4, 5, 6}$ and $B = {0, 1, 2, 3}$ .

Then $A \cup B = {0, 1, 2, 3, 4, 5, 6}$ and $A \cap B = ϕ$ .

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Similar questions

Given A = ${x : x \in N a n d 3 < x \leq 6}$ and B = ${x : x \in W a n d x < 4}$ . Find : (i) Sets A and B in roster form (ii) $A \cup B$ (iii) $A \cap B$ (iv) A - B (v) B - A

Q. Given A = {

x

x \in N

and

3 < x \leq 6

} and B = {

x

x \in W

and

x < 4

}, then find : sets

A

and

B

in roster form.

Q. Find

A \cup B

and

A \cap B

for the following sets.
(i)

A = {0, 1, 2, 4, 6}

and

B = {- 3, - 1, 0, 2, 4, 5}

(ii)

A = {2, 4, 6, 8}

and

B = \emptyset

(iii)

A = {x : x \in N, x \leq 5}

and

B =

{

x : x

is a prime number less than 11}
(iv)

A = {x : x \in N, 2 < x \leq 7}

and

B = {x : x \in W, 0 \leq x \leq 6}

A = {x : x \in N a n d 3 < x \leq 6}

and

B = {x : x \in N a n d x < 4}

. Find

A - B

Given $U = {x : x \in N, x \leq 9},$ $A = {x : x is divisible by 2}$ and $B = {x : \frac{x}{3} \in N},$ where $U$ is the universal set. Then, $(A \cup B) - (A \cap B)$ = ____.

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Given A={x:x∈N and 3<x≤6} and B={x:x∈W and x<4}. Find the sets A and B in roster form also find A∪B and A∩B.

Given A={x:x∈N and 3<x≤6} and B={x:x∈W and x<4}.Then,A={4,5,6} and B={0,1,2,3}.Then A∪B={0,1,2,3,4,5,6} and A∩B=ϕ.

Given $A = {x : x \in N$ and $3 < x \leq 6}$ and $B = {x : x \in W$ and $x < 4}$ . Find the sets $A$ and $B$ in roster form also find $A \cup B$ and $A \cap B$ .

Given $A = {x : x \in N$ and $3 < x \leq 6}$ and $B = {x : x \in W$ and $x < 4}$ .

Then,

$A = {4, 5, 6}$ and $B = {0, 1, 2, 3}$ .

Then $A \cup B = {0, 1, 2, 3, 4, 5, 6}$ and $A \cap B = ϕ$ .