Question

Given :
Area of sector $=15\pi sq.cm$
radius $=6cm$
To find :
Length of the arc corresponding to the sector.

Answer 1

Area of sector $=15\pi c{m}^2$

Radius $=6cm$

$l=nr\left(\frac{\theta }{360}\right)$

Area of sector

as $r^2\left(\frac{\theta }{360}\right)=15\pi$

$6^2\frac{\theta }{360}=15$

${\theta }^o={150}^o$

$\therefore l=\frac{22}{7}\times 6\times \frac{150}{360}$

$\Rightarrow \frac{55}{7}cm$