Given - ABC - P QRAnd AB - PQ -1-3Find the ratio of their area-

AB/PQ=1/3 Now, ar(Δ ABC)/ar(Δ PQR)=AB^2/PQ^2 = (1/3)^2 = 1/9 ...

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Basic Proportionality Theorem

Given Δ ABC ∼...

Question

Given $Δ A B C \sim Δ P Q R$
And $\frac{A B}{P Q} = \frac{1}{3}$
Find the ratio of their area.

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Solution

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Δ A B C \sim Δ P Q R

\frac{A B}{P Q} = \frac{1}{3}

\frac{a r Δ A B C}{a r Δ P Q R}

Δ A B C \sim Δ P Q R,

\frac{A B}{P Q} = \frac{1}{3},

\frac{a r Δ A B C}{a r Δ P Q R}

Δ A B C

\sim

Δ P Q R

\frac{A B}{P Q} = \frac{1}{3}

\frac{a r Δ A B C}{a r Δ P Q R}

Δ A B C \sim Δ P Q R .

(A B C) = 2.25 m^{2}

(P Q R) = 6.25 m^{2}

P Q = 0.5 m

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