CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given:
EoCr3+/Cr=−0.74V;EoMnO−4/Mn2+=1.51V
EoCr2O2+7/Cr3+=1.33V;EoCl/Cl−=1.36V
Based on the data given above, the strongest oxidising agent will be:

A
Mn2+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
MnO4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Cl
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cr3+
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B MnO4
By their given reduction potential it can be seen that as reduction potential of MnO4/Mn2+ is highest means it has highest tendency to reduce and accept electron so it will oxidise other specie easily and it will be the best oxidising agent.
Mn7++5eMn2+
or MnO4+5e+8H+Mn2++4H2O


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nernst Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon