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Question

Given:
EoCr3+/Cr=−0.74V;EoMnO−4/Mn2+=1.51V
EoCr2O2+7/Cr3+=1.33V;EoCl/Cl−=1.36V
Based on the data given above, the strongest oxidising agent will be:

A
Mn2+
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B
MnO4
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C
Cl
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D
Cr3+
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Solution

The correct option is B MnO4
By their given reduction potential it can be seen that as reduction potential of MnO4/Mn2+ is highest means it has highest tendency to reduce and accept electron so it will oxidise other specie easily and it will be the best oxidising agent.
Mn7++5eMn2+
or MnO4+5e+8H+Mn2++4H2O


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