Question

Given equations are $\begin{array}{c}3x-6y=15\\ -2y+4y=-10\end{array}$
How many solution $\left(x,y\right)$ are there to the system of equations above?

• A. zero solution
• B. one solution
• C. Infinite solution
• D. None of these

Answer 1

The correct option is C Infinite solution

$3x-6y=15$

$-2x+4y=-10$

$\frac{a_1}{a_2}=\frac{-3}{2},\frac{b_1}{b_2}=\frac{-6}{4}=\frac{-3}{2},\frac{c_1}{c_2}=\frac{-15}{10}=\frac{-3}{2}$

$\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}$

So, Infinite solutions