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Question

Given f(x)=x0ex(sinx+cosx)dx

Then which of the following is/are correct?

दिया है f(x)=x0ex(sinx+cosx)dx

तब निम्नलिखित में से कौनसा/कौनसे विकल्प सही है/हैं?

A
f(π)=eπ
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B
f(π)=0
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C
f(π2)=eπ2
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D
f(3π2)=e3π2
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Solution

The correct option is D f(3π2)=e3π2

Solution

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