The correct option is C I - U, II - T, III - U, IV - R
I−U,II−T,III−U,IV−R
Since P=V2R⇒R=V2P
Resistance of Bulbs B1,B2,B3 & B4 are R1=1002100=100Ω, R2=100250=200Ω , R100w=100Ω
R3=100225=400, R4=100250=200Ω, R200w=50Ω
With S1 closed S2 open ⇒ε=i Req⇒300=i×300
i=1A⇒ Power output of bulbs is P=i2R
P1=(23)2×100=4009wP2=(23)2×200=8009w
P3=(13)2×400=4009wP4=(13)2×200=2009w