Given i Cu 2- - 2e - - Cu- E o -0-337Vii Cu 2- - e- Cu- E o -0-153VElectrode potential- E 0 for the reaction will be- Cu - - e - - Cu

The correct option is D 0.52V #160;G ^∘ = nFE ^∘ Δ G ^∘_cell= #160; G^o_Cu^2+/Cu G^o_Cu^2+/Cu^+ nF E ^∘_cell= nF E ...

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Given i Cu ...

Question

Given (i) ${C u}^{2 +} + {2 e}^{-} \to C u, E^{o} = + 0.337 V$

(ii) ${C u}^{2 +} + e^{-} \to C u^{+} E^{o} = + 0.153 V$

Electrode potential, $E^{0}$ for the reaction will be:
${C u}^{+} + e^{-} \to C u$

0.38 V

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0.52 V

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0.90 V

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0.30 V

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Solution

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Similar questions

C u^{2 +} + 2 e^{-} ⟶ C u

E^{0} = 0.337 V

C u^{2 +} + e^{-} ⟶ C u^{+}

E^{0} = 0.153 V

E^{0}

C u^{+} + e^{-} ⟶ C u

{C u}^{2 +} + {2 e}^{-} \to C u, E^{\circ} = 0.337 V

{C u}^{2 +} + e^{-} \to C u^{+}, E^{\circ} = 0.153 V

E^{\circ}

{C u}^{+} + e^{-} \to C u,

C u^{2 +} + 2 e^{-} \to C u; E^{o} = 0.337

C u^{2 +} + e^{-} \to C u^{+}; E^{o} = - 0.153

E^{o}

C u^{+} + e \to C u

E^{o}

C u^{2 +} + e^{-} \to C u^{+}

E^{o} = 0.15

C u^{2 +} + 2 e^{-} \to C u

E^{o} = 0.34

E^{o}

C u^{+} + e^{-} \to C u

C u^{2 +} + 2 e^{-} \to C u, E^{\circ} = 0.337 V

C u^{2 +} + e^{-} \to C u^{+}, E^{\circ} = 0.153 V

E^{\circ}

C u^{+} + e^{-} \to C u

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