Given in the figure are two blocks A and B of weight 20N and 100N, respectively. These are being pressed against a wall by a force F as shown. If the coefficient of friction between the blocks is 0.1 and between block B and the wall is 0.15, the frictional force applied by the wall on block B is:
Force on block A, FA=20N
Force on block B, FB=100N
Coefficient of friction between the blocks, m₁=0.1
Coefficient of friction between the block B and the wall, m₂=0.15
For block A,
m₁g=m₁F
20=0.1×F
F=200N
Hence, frictional force on block A in the upward direction=m₁F=0.1×200=20N
Therefore, force on block B in the downward direction.
m₂F=m₂g+m₁F=100+20=120N
Answer C: