Question

Given $\log 2=.3010300,\log 3=.4771213,\log 7=.8450980$, find the value of $\log 14.4$.

Answer 1

$\log \left(14.4\right)=\log \left(\frac{144}{10}\right)=\log \left({12}^2\right)-1=2(\log 3+2\log 2)-1=1.1583626$