Question

Given $\log 2=.3010300,\log 3=.4771213,\log 7=.8450980$, find the value of $\log 4\frac{3}{2}$.

Answer 1

$\log \left(4\frac{2}{3}\right)=\log \left(\frac{14}{3}\right)=\log \left(14\right)-\log 3=\log 2+\log 7-\log 3=0.3010300+0.8450980-0.4771213=0.6690067$