Question

Given $\log 2=.3010300,\log 3=.4771213,\log 7=.8450980$, find the value of $\log \sqrt[3]{312}$.

Answer 1

$\log \left(\sqrt[3]{312}\right)=\frac{1}{3}\log \left(12\right)=\frac{1}{3}(\log 3+2\log 2)=0.359727$