Question

Given $\log 2={}^{.}3010300,\log 3={}^{.}4771213,\log 7={}^{.}8450980,$ find the value of
$\log {}^{.}0125.$

Answer 1

$\log 0.0125=\log \frac{125}{10000}=\log \frac{1}{80}=\log 1-\log 8-\log 10=0-3\log 2-1=-1.9030900$