Question

Given $\log 2={}^{.}3010300,\log 3={}^{.}4771213,\log 7={}^{.}8450980,$ find the value of
$\log 64$.

Answer 1

$\log 64=\log 2^6=6\log 2$

But $\log 2=0.3010300$

$=6\log 2=6\left(0.3010300\right)=1.8061800$