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Question

Given log2=.3010300,log3=.4771213,log7=.8450980, find the value of
log3527.

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Solution

log(3527)=12(log(35)log(27))
=12(log7×5log3+log33)
=12(log7+log(102)3log3)
=12(log7+1log23log3)=0.05635205

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