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Standard XII

Physics

Periodic Motion

Given M is ...

Question

Given $M$ is the mass suspended from a spring of force constant $k$ . The dimensional formula for ${[M / k]}^{1 / 2}$ is same as that for:

frequency

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time period

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velocity

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wavelength

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Solution

The correct option is C time period
$K = \frac{f}{x} = \frac{{M L T}^{- 2}}{L} = {M T}^{- 2}$

$\Rightarrow \frac{M}{K} = \frac{M^{1}}{M^{1} T^{- 2}} = T^{2}$

$\Rightarrow \sqrt{M / K} = T^{1}$

Hence, option B is correct.

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Given M is the mass suspended from a spring of force constant k. The dimensional formula for [M/k]1/2 is same as that for:

The correct option is C time periodK=fx=MLT−2L=MT−2⇒MK=M1M1T−2=T2⇒√M/K=T1Hence, option B is correct.

Given $M$ is the mass suspended from a spring of force constant $k$ . The dimensional formula for ${[M / k]}^{1 / 2}$ is same as that for:

The correct option is C time period
$K = \frac{f}{x} = \frac{{M L T}^{- 2}}{L} = {M T}^{- 2}$

$\Rightarrow \frac{M}{K} = \frac{M^{1}}{M^{1} T^{- 2}} = T^{2}$

$\Rightarrow \sqrt{M / K} = T^{1}$

Hence, option B is correct.