Given P - x - n - N - x -2 n Q - x - n - N - x -4 n where N is a set of natural numbers-Then- P-Q -Q-P is-A- PB- Q C- P - QD-

The correct option is D P = {x: n ∈ nbsp; N, x = nbsp;2n} = 2, 4, 6, 8, 10, 12...... Q = {x: n ∈ nbsp; N, x = nbsp;4n} = 4, 8, 12, 16,20.... where N is ...

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Standard X

Mathematics

Intersection of Sets

Given P = x :...

Question

Given $P = {x : n \in N, x = 2 n}$
$Q = {x : n \in N, x = 4 n}$ where N is a set of natural numbers.
Then, $(P - Q) \cap (Q - P)$ is:

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P \cap Q

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{}

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Solution

The correct option is D {}
$P = {x : n \in N, x = 2 n}$ = {2, 4, 6, 8, 10, 12......}
$Q = {x : n \in N, x = 4 n}$ = {4, 8, 12, 16,20....}
where N is a set of natural numbers
$P - Q$ = { 2, 6, 10, 14,...}
$Q - P$ = {}
$(P - Q) \cap (Q - P)$
={2, 6, 10, 14,...} $\cap$ {}
= {}

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Given P={x:n∈N,x=2n} Q={x:n∈N,x=4n} where N is a set of natural numbers. Then, (P−Q)∩(Q−P) is:

The correct option is D {}P={x:n∈N,x=2n} = {2, 4, 6, 8, 10, 12......} Q={x:n∈N,x=4n} = {4, 8, 12, 16,20....} where N is a set of natural numbers P−Q = { 2, 6, 10, 14,...} Q−P = {} (P−Q)∩(Q−P) ={2, 6, 10, 14,...} ∩{} = {}

Given $P = {x : n \in N, x = 2 n}$
$Q = {x : n \in N, x = 4 n}$ where N is a set of natural numbers.
Then, $(P - Q) \cap (Q - P)$ is:

The correct option is D {}
$P = {x : n \in N, x = 2 n}$ = {2, 4, 6, 8, 10, 12......}
$Q = {x : n \in N, x = 4 n}$ = {4, 8, 12, 16,20....}
where N is a set of natural numbers
$P - Q$ = { 2, 6, 10, 14,...}
$Q - P$ = {}
$(P - Q) \cap (Q - P)$
={2, 6, 10, 14,...} $\cap$ {}
= {}