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Question

Given reaction:
N2(g)+3H2(g)2NH3(g)
What would happen if there is a decrease in volume of container in which reaction occurs?

A
Less NH3 would form
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B
More N2 would form
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C
More NH3 would form
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D
More H2 would form
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Solution

The correct option is C More NH3 would form
Calculating the change in no. of gaseous moles i.e. Δng=24=2 (<0)Δng<0

As,V ngV
So according the Le - chatelier's principle reaction will go towards where ng will decrease.
Since the product side has only two moles of gas, compared to the reactant side which has four gaseous moles.
ng decreases in forward direction.
The reaction would shift towards the product side.

Hence more NH3, i.e. more product will be formed.


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