Given- -2-1-4141-and-6-2-449-find-the-value-of-1-3-2-1 correct to 3 places of decimal-

√(6)=2.449 √(3)×√(2)=2.449 √(3)= 2.449/1.414 =1.731 1/√(3) √(2) 1 = 1//1.731 1.414 1 = 1/ 0.683 = 1/0.683= = 1.464 ...

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Byju's Answer

Standard IX

Mathematics

Operations on Rational and Irrational Numbers

Given, √2=1.4...

Question

Given, $\sqrt{2} = 1.4141 a n d \sqrt{6} = 2.449, f i n d t h e v a l u e o f \frac{1}{\sqrt{3} - \sqrt{2} - 1}$ correct to 3 places of decimal.

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Solution

$\sqrt{6} = 2.449 \sqrt{3} \times \sqrt{2} = 2.449 \sqrt{3} = \frac{2.449}{1.414} = 1.731 \frac{1}{\sqrt{3} - \sqrt{2} - 1} = \frac{1 /}{1.731 - 1.414 - 1} = \frac{1}{- 0.683} = \frac{- 1}{0.683} = = - 1.464$

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Similar questions

Given , $\sqrt{2} = 1.414, \sqrt{3} = 1.732$ and $\sqrt{6} = 2.449$ , find the value of $\frac{1}{\sqrt{3} - \sqrt{2} - 1}$ correct to 3 place of decimal

Q. Given,

\sqrt{2} = 1.414 and \sqrt{6} = 2.449

, find the value of

\frac{1}{\sqrt{3} - \sqrt{2} - 1}

correct to 3 places of decimal.

Q. Given that

\sqrt{3} = 1.7321

, find the correct value to 3 places of decimal of the following.

\sqrt{192} - \frac{1}{2} \sqrt{48} - \sqrt{75}

Find the values of each of the following correct to three places of decimals, it being given that $\sqrt{2} = 1.4142, \sqrt{3} = 1.732, \sqrt{5} = 2.2360, \sqrt{6} = 2.4492 a n d \sqrt{10} = 3.162$ .

(i) $\frac{3 - \sqrt{5}}{3 + 2 \sqrt{5}}$

(ii) $\frac{1 + \sqrt{2}}{3 - 2 \sqrt{2}}$

Using correct to three decimals.

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Given, √2=1.4141 and √6=2.449, find the value of 1√3−√2−1 correct to 3 places of decimal.

√6=2.449√3×√2=2.449√3=2.4491.414=1.7311√3−√2−1=1/1.731−1.414−1=1−0.683=−10.683==−1.464

Given, $\sqrt{2} = 1.4141 a n d \sqrt{6} = 2.449, f i n d t h e v a l u e o f \frac{1}{\sqrt{3} - \sqrt{2} - 1}$ correct to 3 places of decimal.

$\sqrt{6} = 2.449 \sqrt{3} \times \sqrt{2} = 2.449 \sqrt{3} = \frac{2.449}{1.414} = 1.731 \frac{1}{\sqrt{3} - \sqrt{2} - 1} = \frac{1 /}{1.731 - 1.414 - 1} = \frac{1}{- 0.683} = \frac{- 1}{0.683} = = - 1.464$