By a transversal- - 1-120-x- and - 5-5 x0- then the measures of - 1 and - 5 are

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Triangle and Sum of Its Internal Angles

by a transver...

Question

Given that AB || CD, intersected by a transversal. ∠1 = (120 - x)^o and ∠5 = 5x^o, then the measures of ∠1 and ∠5 are

∠1 = 105^o, ∠5 = 105^o

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∠1 = 130^o, ∠5 = 100^o

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∠1 =130^o, ∠5 = 120^o

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∠1 =100^o, ∠5 = 100^o

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Solution

The correct option is D
∠1 =100^o, ∠5 = 100^o

∠1 = ∠5 (corresponding angles)

(120 - x)^o = 5x^o then x = 20

Substituting the value of x

The measures of ∠1 and ∠5 are 100^o each.

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Given that AB || CD, intersected by a transversal. ∠1 = (120 - x)o and ∠5 = 5xo, then the measures of ∠1 and ∠5 are

The correct option is D ∠1 =100o, ∠5 = 100o ∠1 = ∠5 (corresponding angles) (120 - x)o = 5xo then x = 20 Substituting the value of x The measures of ∠1 and ∠5 are 100o each.

Given that AB || CD, intersected by a transversal. ∠1 = (120 - x)^o and ∠5 = 5x^o, then the measures of ∠1 and ∠5 are

The correct option is D
∠1 =100^o, ∠5 = 100^o

∠1 = ∠5 (corresponding angles)

(120 - x)^o = 5x^o then x = 20

Substituting the value of x

The measures of ∠1 and ∠5 are 100^o each.