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Byju's Answer
Standard XII
Chemistry
Enthalpy of Neutralisation
Given that C...
Question
Given that
C
+
O
2
⟶
C
O
2
;
Δ
H
∘
=
−
x
k
J
2
C
O
+
O
2
⟶
2
C
O
2
;
Δ
H
∘
=
−
y
k
J
The heat of formation of carbon monoxide will be:
A
y
−
2
x
2
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B
y
+
2
x
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C
2
x
−
y
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D
2
x
−
y
2
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Solution
The correct option is
A
y
−
2
x
2
Given,
C
+
O
2
⟶
C
O
2
;
Δ
H
=
−
x
k
J
.....(i)
2
C
O
+
O
2
⟶
2
C
O
2
;
Δ
H
4
=
−
y
k
J
.....(ii)
Required equation is
C
+
1
2
O
2
⟶
C
O
,
Δ
H
1
=
?
On reversing equation (ii), we get
2
C
O
2
⟶
2
C
O
+
O
2
;
Δ
H
2
=
+
y
k
J
......(iii)
Dividing equation (iii) by 2 gives
C
O
2
⟶
C
O
+
1
2
O
2
;
Δ
H
3
=
+
y
2
k
J
......(iv)
On adding equation (i) and (iv), we get (required equation)
C
+
1
2
O
2
⟶
C
O
;
Δ
H
1
=
Δ
H
+
Δ
H
3
=
(
−
x
+
y
2
)
k
J
=
y
−
2
x
2
k
J
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Similar questions
Q.
Given that: (i)
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
∘
=
−
x
k
J
(ii)
2
C
O
(
g
)
+
O
2
(
g
)
→
2
C
O
2
(
g
)
;
Δ
H
∘
=
−
y
k
J
. The enthalpy of formation of carbon monoxide will be :
Q.
Given that: (i)
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
∘
=
−
x
k
J
(ii)
2
C
O
(
g
)
+
O
2
(
g
)
→
2
C
O
2
(
g
)
;
Δ
H
∘
=
−
y
k
J
. The enthalpy of formation of carbon monoxide will be :
Q.
S
+
3
2
O
2
→
S
O
3
+
2
x
kcal;
S
O
2
+
1
2
O
2
→
S
O
3
+
y
kcal
The heat of formation of
S
O
2
is:
Q.
The heat of transition (
Δ
H
t
) of graphite into diamond would be,
where,
C
(
g
r
a
p
h
i
t
e
)
+
O
2
(
g
)
→
C
O
2
(
g
)
Δ
H
=
x
k
J
C
(
d
i
a
m
o
n
d
)
+
O
2
(
g
)
→
C
O
2
(
g
)
Δ
H
=
y
k
J
Q.
Using the information given in the reaction equations below, calculate the heat of formation for
1
mole of carbon monoxide
C
O
.
2
C
(
s
)
+
2
O
2
→
2
C
O
2
Δ
H
r
x
n
=
−
787
k
J
2
C
O
+
O
2
→
2
C
O
2
Δ
H
r
x
n
=
−
566
k
J
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