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Question

Given that cos50o20′=0.6388 and cos50o42′=0.6334, then the possible value of cos50o20′ is

A
0.6293
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B
0.6307
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C
0.6361
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D
0.6414
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Solution

The correct option is B 0.6361
cos(50018)=0.6388
cos(50042)=0.6334
The possible value of cos(50020) must lie between cos(50018) and cos(50042). Thus the only possible value is 0.6361

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