Given that -3-1-732- then -147-14-48-75 is equal to

The correct option is C 1.732 √(147) 14√(48) √(75) =√(3×49) 14√(3×16) √(3×25) =7√(3) 14×4√(3) 5√(3) =7√(3) √(3) 5√(3) =7√(3) 6√(3) ...

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Byju's Answer

Standard IX

Mathematics

Laws of Exponents for Real Numbers

Given that ...

Question

Given that $\sqrt{3} = 1.732$ , then $(\sqrt{147} - \frac{1}{4} \sqrt{48} - \sqrt{75})$ is equal to

5.196

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3.464

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1.732

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0.866

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Solution

The correct option is C $1.732$
$\sqrt{147} - \frac{1}{4} \sqrt{48} - \sqrt{75}$
$= \sqrt{3 \times 49} - \frac{1}{4} \sqrt{3 \times 16} - \sqrt{3 \times 25}$
$= 7 \sqrt{3} - \frac{1}{4} \times 4 \sqrt{3} - 5 \sqrt{3}$
$= 7 \sqrt{3} - \sqrt{3} - 5 \sqrt{3}$
$= 7 \sqrt{3} - 6 \sqrt{3}$
$= \sqrt{3}$
$= 1.732$

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Given that √3=1.732, then (√147−14√48−√75) is equal to

The correct option is C 1.732√147−14√48−√75=√3×49−14√3×16−√3×25=7√3−14×4√3−5√3=7√3−√3−5√3=7√3−6√3=√3=1.732

Given that $\sqrt{3} = 1.732$ , then $(\sqrt{147} - \frac{1}{4} \sqrt{48} - \sqrt{75})$ is equal to