Given- that E- O2-H2O-1-23V-E-S2O82-SO42-2-05 V-E- Br2-Br-1-09 VE-Au3-Au-1-4 VThe strongest oxidising agent is-

Higher the standard reduction potential (E^∘_M^n+/M), better is oxidising agent among the given, nbsp; E^∘_S_2O_8^2 /SO_4^2 is highest, hence S_2O_8^2 is th ...

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Standard XII

Chemistry

Oxidation and Reduction

Given, that E...

Question

Given, that $E_{O_{2} / H_{2} O}^{\circ} = + 1.23 V;$

$E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{\circ} = 2.05 V;$

$E_{B r_{2} / B r^{⊝}}^{\circ} = + 1.09 V$

$E_{A u^{3 +} / A u}^{\circ} = + 1.4 V$

The strongest oxidising agent is:

A u^{3 +}

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O_{2}

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S_{2} O_{8}^{2 -}

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B r_{2}

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Solution

The correct option is C $S_{2} O_{8}^{2 -}$
Higher the standard reduction potential $(E_{M^{n +} / M}^{\circ})$ , better is oxidising agent among the given, $E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{\circ}$ is highest, hence $S_{2} O_{8}^{2 -}$ is the strongest oxidising agent.
The decreasing order of oxidising agent among the given option is as follows:
$S_{2} O_{8}^{2 -} > A u^{3 +} > O_{2} > B r_{2}$

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Similar questions

Q. Given that

E_{O_{2} / H_{2} O}^{o} = + 1.23 V

;

E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{o} = + 2.05 V

;

E_{B r_{2} / B r^{-}}^{o} = + 1.09 V

;

E_{A u^{3 +} / A u}^{o} = + 1.4 V

. The strongest oxidizing agent is:

Q. Given that

E_{O_{2} / H_{2} O}^{o} = + 1.23 V;

E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{o} = 2.05 V

E_{B r_{2} / B r^{-}}^{o} = + 1.09 V

E_{A u^{3 +} / A u}^{o} = + 1.4 V

The strongest oxidising agent is:

Q. Given that

E_{O_{2} / H_{2} O}^{o} = + 1.23 V

;

E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{o} = + 2.05 V

;

E_{B r_{2} / B r^{-}}^{o} = + 1.09 V

;

E_{A u^{3 +} / A u}^{o} = + 1.4 V

. The strongest oxidizing agent is:

Q. If

E_{A u^{+} / A u}^{\circ}

is 1.69 V &

E_{A u^{3 +} / A u}^{\circ}

is 1.40 V, then

E_{A u^{3 +} / A u^{+}}^{\circ}

will be:

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

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Given, that E∘O2/H2O=+1.23V; E∘S2O2−8/SO2−4=2.05 V; E∘Br2/Br⊝=+1.09 V E∘Au3+/Au=+1.4 V The strongest oxidising agent is:

Given, that $E_{O_{2} / H_{2} O}^{\circ} = + 1.23 V;$

$E_{S_{2} O_{8}^{2 -} / S O_{4}^{2 -}}^{\circ} = 2.05 V;$

$E_{B r_{2} / B r^{⊝}}^{\circ} = + 1.09 V$

$E_{A u^{3 +} / A u}^{\circ} = + 1.4 V$

The strongest oxidising agent is: