Given that first term of the AP is 7 & the common difference is 12.Find n if $n^{t h}$ term of an AP is 295.

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Solution

The correct option is C
25

Given a = 7 & d = 12;

$n^{t h}$ term = 295;

a + ( n – 1 ) d = 295

7 + ( n – 1 )12 = 295

7 + 12n – 12 = 295

12n = 300

n = 25

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Given that first term of the AP is 7 & the common difference is 12.Find n if nth term of an AP is 295.

The correct option is C 25 Given a = 7 & d = 12; nth term = 295; a + ( n – 1 ) d = 295 7 + ( n – 1 )12 = 295 7 + 12n – 12 = 295 12n = 300 n = 25

Given that first term of the AP is 7 & the common difference is 12.Find n if $n^{t h}$ term of an AP is 295.

The correct option is C
25

Given a = 7 & d = 12;

$n^{t h}$ term = 295;

a + ( n – 1 ) d = 295

7 + ( n – 1 )12 = 295

7 + 12n – 12 = 295

12n = 300

n = 25