Given that, heat of neutralisation of strong acid and strong base is $57.1 k J$ . Calculate the heat produced when $0.25$ mole of $H C l$ is neutralised with $0.25$ mole of $N a O H$ in aqueous solution:

22.5 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

57 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.275 k J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

28.55 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $14.275 k J$
Neutralisation reaction is,
$N a O H + H C l \to H_{2} O + N a C l$ $Δ H = 57.1 K J$
This means that when 1 mole of NaOH reacts with 1 mole of HCl the energy released is = $57.1 K J$
Hence, when 0.25 moles of HCl reacts with 0.25 moles of NaOH then the energy released would be given by,
$Δ H = 0.25 \times 57.1 = 14.275 K J .$
Hence, answer is option C.

Suggest Corrections

Similar questions

Q. For strong acid strong base neutralisation energy for

1

mole

H_{2} O

formation is

- 57.1 k J

. If

0.25

mole of strong monoprotic acid is reacted with

0.5

mole of strong base then enthalpy of neutralisation is:

Heat of Neutralisation of strong Acid and strong base is $- 57 K J$ . The amount of heat released when $0.5 m o l e$ of $H N O_{3}$ solution is added to $0.2 m o l e$ of $N a O H$ solution is

Q. The heat of neutralization of a strong base and a strong acid is

13.7

kcal. The heat released when

0.6

mole HCl solution is added to

0.25

mole of NaOH is:

The heat of neutralization of a strong base and a strong acid is 57 kJ. The heat released, when 0.5 mole of $H N O_{3}$ solution is added to 0.20 moles of NaOH solution, is:

Q. Assertion :Heat of neutralisation of nitric acid with

N a O H

is same to that of

H C l

and

N a O H

. Reason: In both cases strong acid and strong base are neutralised.

H^{+} + {O H}^{-} \to H_{2} O

Join BYJU'S Learning Program

Given that, heat of neutralisation of strong acid and strong base is 57.1kJ. Calculate the heat produced when 0.25 mole of HCl is neutralised with 0.25 mole of NaOH in aqueous solution:

Given that, heat of neutralisation of strong acid and strong base is $57.1 k J$ . Calculate the heat produced when $0.25$ mole of $H C l$ is neutralised with $0.25$ mole of $N a O H$ in aqueous solution: