Question

Given that $K_w$ for water is ${10}^{-13}{M}^2$ at $2^{o}C$, compute the sum of $pOH$ and $pH$ for a neutral aqueous solution at $2^{o}C$?

• A. $7.0$
• B. $13.30$
• C. $14.0$
• D. $13.0$

Answer 1

The correct option is D $13.0$

As we know,
$K_w=\left[H^{+}\right]\left[O{H}^{-}\right];pH+pOH=-log{K}_w=13$.