wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given that p is a prime number. p2[p27-] is always divisible by?

A
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
27
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D none of these

According to fermat's theorem " If P is a prime number and N is prime to P, then NP - N is divisible by P."

Open the brackets, p2[p27-] = p29-p will always be divisible by 29, as it is prime.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorising Numerator
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon