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Question

Given that the abundances of isotopes 54Fe,56Fe and 57Fe are 5%,90% and 5% respectively, the atomic mass of Fe is:

A
55.85
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B
55.95
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C
55.75
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D
56.05
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Solution

The correct option is B 55.95
¯A=Aixixi
¯A=54×0.05+56×0.90+57×0.05
¯A=55.95

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