Given that the H.C.F. of 35 and 49 is 7, what is their LCM?
195
245
265
225
We know that the product of two numbers is equal to the product of their HCF and LCM.
So 35 × 49 = 7 × LCM
Hence, LCM=245
H.C.F of a2b3 and a3b2d7 is a2b2. What is their H.C.F