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Question

Given that y=(cx+d)b,where b0.

If ax+by+c=0 , where (a+c)0,
then what is the value of x ?

A
(d+c)(a+c)
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B
(dc)(a+c)
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C
(a+c)(d+c)
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D
(d+c)(a+c)
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Solution

The correct option is B (dc)(a+c)
Given ax+by+c=0.
Also given that y=(cx+d)b.
Substituting this in ax+by+c=0,
we get
ax+[b(cx+d)b]+c=0.

So, ax+cx+d+c=0
(a+c)x=dc
x=(dc)(a+c)

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