Given the area of a rectangle is, $A = 3 p^{2} + 9 p + 6$ . The length is given as ( $3 p + 3$ ). Therefore, the width is:

5a - 3

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5a - 4

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4a - 5

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a - 4

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Solution

The correct option is B
5a - 4

Let y be the width.
Since area is given as $3 p^{2} + 9 p + 6$ which is the product of $y$ and $(3 p + 3),$ we have;
$y (3 p + 3) = 3 p^{2} + 9 p + 6$
To find y, we need to do a long division of $3 p^{2} + 9 p + 6$ by (3p+3).

$∴ y = p + 2$

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