Given the data 250C Ag-I- AgI-e- E0-0-152V Ag- Ag-e- E0-0-800VWhat is the value of log Ksp for AgI-

The correct option is B 7.13× 10^ 17 The cell reaction is, nbsp; AgI Ag ^ + + I ^ . The standard emf of cell is, nbsp; E _ cell ^ 0 ...

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Equilibrium Constant from Nernst Equation

Given the dat...

Question

Given the data $25^{0} C$
$A g + I^{-} \to A g I + e^{-}, E^{0} = 0.152 V$
$A g \to A g^{+} e^{-}, E^{0} = 0.800 V$
What is the value of log $K_{s p}$ for AgI?

3.83 \times 10^{- 13}

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7.13 \times 10^{- 17}

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8. 12 \times 10^{- 11}

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8. 612 \times 10^{- 9}

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Solution

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Similar questions

25^{0} C

A g + I^{-} \to A g I + e^{-}; E^{0} = 0.152 V

A g \to A g^{+} + e^{-}; E^{0} = - 0.800 V

K_{s p}

A g I

(G i v e n : 2.303 R T / F = 0.059 V)

Given the data at $25^{\circ} C$

$A g + I^{-} \to A g I + e^{-}; E^{0} = 0.152 v$

$A g \to A g^{+} + e^{-}; E^{0} = - 0.800 v$

What is the value of $log k_{s p} f o r A g I ?$

$(2.303 R T / F = 0 .059 v)$

25^{o}

A g_{(s)} + I_{(a q)} \to A g I_{(s)} + e^{-}, E^{o} = 0.152

A g_{(s)} \to A g_{(a q)}^{+} + e^{-}, E^{o} = - 0.800

K_{s p}

(W h e r e K_{s p} = solubility product, 2.303 \frac{R T}{F} = 0.059 V)

A g^{+} (a q) + e^{-} \to A g (s)

E^{0} = + 0.799 V

A g C l (s) + e^{-} \to A g (s) + C l^{-} (a q)

E^{0} = + 0.222 V

1.743 \times 10^{- 10}

p K_{s p}

E^{\circ}

A g^{+} / A g

E^{\circ}

A g I + e^{-} \to A g + I^{-}

149 \times 10^{- x}

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