Given the following multi-step reaction mechanism, which of the following can be classified as an intermediate?
$O_{2} \to O + O$
$S O_{2} + 2 O \to S O_{4}$
$S O_{4} + S O_{2} \to 2 S O_{3}$

O

is the intermediate.

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S O_{4}

is the intermediate.

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Both

O

and

S O_{4}

are intermediates.

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There are no intermediates in the reaction mechanism.

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Solution

The correct option is C Both $O$ and $S O_{4}$ are intermediates.
Given mechanism,

$O_{2} ⟶ O + O$

${S O}_{2} + 2 O ⟶ {S O}_{4}$

$S O_{4} + S O_{2} ⟶ {2 S O}_{3}$

Overall reaction: $O_{2} + 2 S O_{2} ⟶ {2 S O}_{3}$

In the above overall reaction, $O$ and $S O_{4}$ does not appear in the overall reaction but are formed during the reaction progresses.
Therefore, $O$ and $S O_{4}$ match the definition of intermediates.

Therefore, (C) is the correct answer.

Suggest Corrections

Similar questions

O_{3} (g) ⇌ O_{2} (g) + O (g)

O (g) + O_{3} (g) \to 2 O_{2}

H_{2} {S O}_{4}

E (e n z y m e) + S (r e a c t a n t) ⇌ E S (i n t e r m e d i a t e - 1)

E S (i n t e r m e d i a t e - 1) ⇌ E P (i n t e r m e d i a t e - 2)

E P (i n t e r m e d i a t e - 2) ⇌ E (e n z y m e) + P (p r o d u c t)

C u + H_{2} {S O}_{4} - \to C u S O_{4} + {S O}_{2} ↑ + H_{2} O

F e + + H_{2} O - \to {F e}_{3} O_{4} + H_{2} ↑

{C H}_{4} + O_{2} \to C O_{2} + H_{2} O

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